\(\int \frac {1}{(3+3 \sin (e+f x))^2} \, dx\) [466]

Optimal result

Integrand size = 12, antiderivative size = 51 \[ \int \frac {1}{(3+3 \sin (e+f x))^2} \, dx=-\frac {\cos (e+f x)}{3 f (3+3 \sin (e+f x))^2}-\frac {\cos (e+f x)}{3 f (9+9 \sin (e+f x))} \]

[Out]

-1/3*cos(f*x+e)/f/(a+a*sin(f*x+e))^2-1/3*cos(f*x+e)/f/(a^2+a^2*sin(f*x+e))

Rubi [A] (verified)

Time = 0.02 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.08, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2729, 2727} \[ \int \frac {1}{(3+3 \sin (e+f x))^2} \, dx=-\frac {\cos (e+f x)}{3 f \left (a^2 \sin (e+f x)+a^2\right )}-\frac {\cos (e+f x)}{3 f (a \sin (e+f x)+a)^2} \]

[In]

Int[(a + a*Sin[e + f*x])^(-2),x]

[Out]

-1/3*Cos[e + f*x]/(f*(a + a*Sin[e + f*x])^2) - Cos[e + f*x]/(3*f*(a^2 + a^2*Sin[e + f*x]))

Rule 2727

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> Simp[-Cos[c + d*x]/(d*(b + a*Sin[c + d*x])), x]
/; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2, 0]

Rule 2729

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[b*Cos[c + d*x]*((a + b*Sin[c + d*x])^n/(a*d
*(2*n + 1))), x] + Dist[(n + 1)/(a*(2*n + 1)), Int[(a + b*Sin[c + d*x])^(n + 1), x], x] /; FreeQ[{a, b, c, d},
x] && EqQ[a^2 - b^2, 0] && LtQ[n, -1] && IntegerQ[2*n]

Rubi steps \begin{align*} \text {integral}& = -\frac {\cos (e+f x)}{3 f (a+a \sin (e+f x))^2}+\frac {\int \frac {1}{a+a \sin (e+f x)} \, dx}{3 a} \\ & = -\frac {\cos (e+f x)}{3 f (a+a \sin (e+f x))^2}-\frac {\cos (e+f x)}{3 f \left (a^2+a^2 \sin (e+f x)\right )} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.16 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00 \[ \int \frac {1}{(3+3 \sin (e+f x))^2} \, dx=-\frac {-3+4 \cos (e+f x)+\cos (2 (e+f x))-4 \sin (e+f x)+\sin (2 (e+f x))}{54 f (1+\sin (e+f x))^2} \]

[In]

Integrate[(3 + 3*Sin[e + f*x])^(-2),x]

[Out]

-1/54*(-3 + 4*Cos[e + f*x] + Cos[2*(e + f*x)] - 4*Sin[e + f*x] + Sin[2*(e + f*x)])/(f*(1 + Sin[e + f*x])^2)

Maple [C] (verified)

Result contains complex when optimal does not.

Time = 0.58 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.75

method	result	size
risch	\(-\frac {2 i \left (i+3 \,{\mathrm e}^{i \left (f x +e \right )}\right )}{3 f \,a^{2} \left ({\mathrm e}^{i \left (f x +e \right )}+i\right )^{3}}\)	\(38\)
parallelrisch	\(\frac {-4-6 \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )-6 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{3 f \,a^{2} \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{3}}\)	\(48\)
derivativedivides	\(\frac {-\frac {2}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1}+\frac {2}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{2}}-\frac {4}{3 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{3}}}{a^{2} f}\)	\(53\)
default	\(\frac {-\frac {2}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1}+\frac {2}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{2}}-\frac {4}{3 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{3}}}{a^{2} f}\)	\(53\)
norman	\(\frac {-\frac {2 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{f a}-\frac {2 \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f a}-\frac {4}{3 a f}}{a \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{3}}\)	\(63\)

[In]

int(1/(a+a*sin(f*x+e))^2,x,method=_RETURNVERBOSE)

[Out]

-2/3*I*(I+3*exp(I*(f*x+e)))/f/a^2/(exp(I*(f*x+e))+I)^3

Fricas [A] (verification not implemented)

none

Time = 0.25 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.86 \[ \int \frac {1}{(3+3 \sin (e+f x))^2} \, dx=\frac {\cos \left (f x + e\right )^{2} + {\left (\cos \left (f x + e\right ) - 1\right )} \sin \left (f x + e\right ) + 2 \, \cos \left (f x + e\right ) + 1}{3 \, {\left (a^{2} f \cos \left (f x + e\right )^{2} - a^{2} f \cos \left (f x + e\right ) - 2 \, a^{2} f - {\left (a^{2} f \cos \left (f x + e\right ) + 2 \, a^{2} f\right )} \sin \left (f x + e\right )\right )}} \]

[In]

integrate(1/(a+a*sin(f*x+e))^2,x, algorithm="fricas")

[Out]

1/3*(cos(f*x + e)^2 + (cos(f*x + e) - 1)*sin(f*x + e) + 2*cos(f*x + e) + 1)/(a^2*f*cos(f*x + e)^2 - a^2*f*cos(
f*x + e) - 2*a^2*f - (a^2*f*cos(f*x + e) + 2*a^2*f)*sin(f*x + e))

Sympy [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 221 vs. \(2 (46) = 92\).

Time = 0.69 (sec) , antiderivative size = 221, normalized size of antiderivative = 4.33 \[ \int \frac {1}{(3+3 \sin (e+f x))^2} \, dx=\begin {cases} - \frac {6 \tan ^{2}{\left (\frac {e}{2} + \frac {f x}{2} \right )}}{3 a^{2} f \tan ^{3}{\left (\frac {e}{2} + \frac {f x}{2} \right )} + 9 a^{2} f \tan ^{2}{\left (\frac {e}{2} + \frac {f x}{2} \right )} + 9 a^{2} f \tan {\left (\frac {e}{2} + \frac {f x}{2} \right )} + 3 a^{2} f} - \frac {6 \tan {\left (\frac {e}{2} + \frac {f x}{2} \right )}}{3 a^{2} f \tan ^{3}{\left (\frac {e}{2} + \frac {f x}{2} \right )} + 9 a^{2} f \tan ^{2}{\left (\frac {e}{2} + \frac {f x}{2} \right )} + 9 a^{2} f \tan {\left (\frac {e}{2} + \frac {f x}{2} \right )} + 3 a^{2} f} - \frac {4}{3 a^{2} f \tan ^{3}{\left (\frac {e}{2} + \frac {f x}{2} \right )} + 9 a^{2} f \tan ^{2}{\left (\frac {e}{2} + \frac {f x}{2} \right )} + 9 a^{2} f \tan {\left (\frac {e}{2} + \frac {f x}{2} \right )} + 3 a^{2} f} & \text {for}\: f \neq 0 \\\frac {x}{\left (a \sin {\left (e \right )} + a\right )^{2}} & \text {otherwise} \end {cases} \]

[In]

integrate(1/(a+a*sin(f*x+e))**2,x)

[Out]

Piecewise((-6*tan(e/2 + f*x/2)**2/(3*a**2*f*tan(e/2 + f*x/2)**3 + 9*a**2*f*tan(e/2 + f*x/2)**2 + 9*a**2*f*tan(
e/2 + f*x/2) + 3*a**2*f) - 6*tan(e/2 + f*x/2)/(3*a**2*f*tan(e/2 + f*x/2)**3 + 9*a**2*f*tan(e/2 + f*x/2)**2 + 9
*a**2*f*tan(e/2 + f*x/2) + 3*a**2*f) - 4/(3*a**2*f*tan(e/2 + f*x/2)**3 + 9*a**2*f*tan(e/2 + f*x/2)**2 + 9*a**2
*f*tan(e/2 + f*x/2) + 3*a**2*f), Ne(f, 0)), (x/(a*sin(e) + a)**2, True))

Maxima [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 117 vs. \(2 (51) = 102\).

Time = 0.19 (sec) , antiderivative size = 117, normalized size of antiderivative = 2.29 \[ \int \frac {1}{(3+3 \sin (e+f x))^2} \, dx=-\frac {2 \, {\left (\frac {3 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac {3 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} + 2\right )}}{3 \, {\left (a^{2} + \frac {3 \, a^{2} \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac {3 \, a^{2} \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} + \frac {a^{2} \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}}\right )} f} \]

[In]

integrate(1/(a+a*sin(f*x+e))^2,x, algorithm="maxima")

[Out]

-2/3*(3*sin(f*x + e)/(cos(f*x + e) + 1) + 3*sin(f*x + e)^2/(cos(f*x + e) + 1)^2 + 2)/((a^2 + 3*a^2*sin(f*x + e
)/(cos(f*x + e) + 1) + 3*a^2*sin(f*x + e)^2/(cos(f*x + e) + 1)^2 + a^2*sin(f*x + e)^3/(cos(f*x + e) + 1)^3)*f)

Giac [A] (verification not implemented)

none

Time = 0.30 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.92 \[ \int \frac {1}{(3+3 \sin (e+f x))^2} \, dx=-\frac {2 \, {\left (3 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 3 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 2\right )}}{3 \, a^{2} f {\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1\right )}^{3}} \]

[In]

integrate(1/(a+a*sin(f*x+e))^2,x, algorithm="giac")

[Out]

-2/3*(3*tan(1/2*f*x + 1/2*e)^2 + 3*tan(1/2*f*x + 1/2*e) + 2)/(a^2*f*(tan(1/2*f*x + 1/2*e) + 1)^3)

Mupad [B] (verification not implemented)

Time = 6.78 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.49 \[ \int \frac {1}{(3+3 \sin (e+f x))^2} \, dx=-\frac {2\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )-\frac {2\,\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left ({\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2-3\right )}{3}}{a^2\,f\,{\left (\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )+\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )\right )}^3} \]

[In]

int(1/(a + a*sin(e + f*x))^2,x)

[Out]

-(2*cos(e/2 + (f*x)/2)^2*sin(e/2 + (f*x)/2) - (2*cos(e/2 + (f*x)/2)*(cos(e/2 + (f*x)/2)^2 - 3))/3)/(a^2*f*(cos
(e/2 + (f*x)/2) + sin(e/2 + (f*x)/2))^3)